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1 July, 22:20

Enterprising students set an enormous slip-n-slide (a plastic sheetcovered in water to reduce friction) on flat ground. If the slip-n-slideis 250 m long, how small does the average acceleration have to be fora student starting at 5 m/s to slide to the end

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  1. 2 July, 01:14
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    a = - 0.05 m/s² (negative sign shows deceleration)

    Explanation:

    In order, to find out the minimum average acceleration for a student starting at 5 m/s to slide to the end, we can use 3rd equation of motion. 3rd equation of motion is given as follows:

    2as = Vf² - Vi²

    where,

    a = minimum acceleration required = ?

    s = minimum distance covered = 250 m

    Vf = Final Speed = 0 m/s (for minimum acceleration the student will barely cover 250 m and then stop)

    Vi = Initial Velocity = 5 m/s

    Therefore,

    2a (250 m) = (0 m/s) ² - (5 m/s) ²

    a = - (25 m²/s²) / (500 m)

    a = - 0.05 m/s² (negative sign shows deceleration)
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