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15 July, 21:16

A (n) 0.212 kg baseball is thrown with a speed of 18.8 m/s. It is hit straight back at the pitcher with a final speed of 21.2 m/s. What is the magnitude of the impulse delivered to the ball?

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  1. 15 July, 23:31
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    Impulse will be 8.4788 kgm/sec

    Explanation:

    We have given mass of the ball m = 0.212 kg

    Initial velocity u = 18.8 m/sec

    We know that momentum P = mass*velocity

    Taking initial velocity as negative

    So initial momentum = 0.212*-18.8 = - 3.9856 kgm/sec

    Final velocity is given as v = 21.2 m/sec

    So final momentum = 0.212*21.2 = 4.4944 kgm/sec

    We know that impulse is given by change in momentum

    So impulse = final momentum-initial momentum = 4.4944 - (-3.9844) = 8.4788 kgm/sec
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