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19 March, 22:50

two punds of water vapor at 30 psia fill the 4ft3 left chmaber of a partitioned system. The right chmaber has twice the volume of the left and is initially evacuated. Detrmine the pressure of water after the paertiion has been removed nd enough heat has been transfered so that the temperature of the water is 40F.

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  1. 20 March, 01:39
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    pressure of water will be 49.7 atm

    Explanation:

    given data

    pressure = 30 psi = 2.04 atm

    water = 2 pound = 907.18

    mole of water vapor = 907.19 / 2 = 50.4 mole

    volume = 4 ft³ = 113.2 L

    temperature = 40 F = 277.59 K

    to find out

    pressure of water

    solution

    we will apply here ideal gas condition

    that is

    PV = nRT ... 1

    put here all value and here R = 0.0821, T temperature and V volume and P pressure and n is no of mole

    and we get here temperature

    PV = nRT

    2.04 * 113.2 = 50.4*0.0821*T

    solve it and we get

    T = 55.8 K

    so we have given right chamber has twice the volume of the left chamber i. e

    volume = twice of volume + volume

    volume = 2 (113.2) + 113.2

    volume = 339.6 L

    so from equation 1 pressure will be

    PV = nRT

    P (339.6) = 50.4 * (0.0821) * (277.59)

    P = 3.3822 atm = 49.7 atm

    so pressure of water will be 49.7 atm
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