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4 August, 20:47

An 835 kg dragster accelerates from rest to 110 km/h in 0.90 seconds.

a. what is the change in momentum of the car?

b. what is the average force exerted on the car?

c. what exerts that force?

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  1. 4 August, 22:28
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    Answer

    given,

    mass of the dragster = 835 Kg

    initial speed, u = 0 m/s

    final speed, v = 110 km/h = 110 x 0.278 = 30.58 m/s

    time, t = 0.90 s

    a) Change in momentum

    Δ P = m v - m u

    Δ P = 835 x (30.58 - 0)

    Δ P = 25534.3 kg. m/s

    b) average force exerted on the car

    change in momentum = Force x time

    25534.3 = F x 0.9

    F = 28371.44 N

    c) The exerted force is due to friction because the motion of the dragster is because of friction.
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