On a day when the barometer reads 75.23 cm, a reaction vessel holds 250 mL of ideal gas at 20 celsius. An oil manometer (rho = 810 kg/m^3) reads the pressure in the vessel to be 41 cm of oil and below atmospheric pressure. What volume will the gas occupy under S. T. P.?

Question

Physics

Harrison Porter

2 December, 16:55

On a day when the barometer reads 75.23 cm, a reaction vessel holds 250 mL of ideal gas at 20 celsius. An oil manometer (rho = 810 kg/m^3) reads the pressure in the vessel to be 41 cm of oil and below atmospheric pressure. What volume will the gas occupy under S. T. P.?

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Answers (1)

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Kamron Baker · Answer 1

V2 = 8.25 ml

Explanation:

First we will list down the data that is given to us:

V1 = 250 ml

T1 = 20° C + 273K = 293K

T2 = 25° C + 273K = 298K (AT STP)

Density at STP = 13600 kg/m^3

First we will calculate the pressure inside the vessel using the formula

P = (ρ) (g) (h)

P1 = (810) (9.8) (0.41)

P1 = 3254.58 pa

P2 = (13600) (9.8) (0.7523)

P2 = 100266.544 pa

Now in order calculate the volume that the gas occupies we will use the following formula,

(P1*V1) / T1 = (P2*V2) / T2

Making V2 as the subject of the equation we get,

V2 = (P1*V1*T2) / (P2*T1)

V2 = (3254.58*250*298) / (100266.544*293)

V2 = 8.25 ml