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17 May, 17:45

An electric dipole, consisting of charges each of magnitude 2.11 nC and separated by 8.37 micrometers, is in an electric field of strength 1578 N/C. What is the magnitude of the difference in potential energy (in Joules) corresponding to dipole orientations parallel to and anti-parallel to the electric field

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  1. 17 May, 20:46
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    54*10^-13 J

    Explanation:

    given:

    charge = 2.11 nC

    distance=8.37*10-6

    electric field intensity=1578 N/C

    solution:

    dipole moment magnitude=q. 2a

    =2.11 nC*2*8.37*10-6

    =18*10^-15

    potential energy of dipole = - P*E

    = - P*E*cos Ф

    for parallel orientation, Ф=0

    potential energy = - 18*10^-15*300*cos 0

    =-54*10^-13 J

    for perpendicular orientation, Ф=90

    potential energy = - 18*10^-15*300*cos 90

    =0

    difference = 0 - (-54*10^-13) J

    =54*10^-13 J
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