Ask Question
Today, 11:28

What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.)

+4
Answers (1)
  1. Today, 11:37
    0
    0.900 mol/kg

    Explanation:

    Molality is moles of solute per kilograms of solvent.

    Converting 54 grams of NaOH to moles:

    54 g NaOH * (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH

    So the molality is:

    m = (1.35 mol) / (1.50 kg)

    m = 0.900 mol/kg
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.) ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers