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1 April, 15:16

In tae-kwon-do, a hand is slammed down onto a target at a speed of 10.5 m/s and comes to a stop during the 2.13 ms collision. Assume that during the impact the hand is independent of the arm and has a mass of 0.400 kg. What is the magnitude of the impulse?

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  1. 1 April, 16:14
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    4.2 kg. m/s

    Explanation:

    The impulse is the vector greatness that relates force and time, and the momentum is the vector greatness that relates the mass and the velocity of a body. The impulse theorem relates the impulse with the momentum (Q) by the expression:

    I = ΔQ

    The momentum is Q = mxv, where m is the mass and v the velocity. How the hand stops, the final velocity must be 0, so:

    I = mxvf - mxvi

    I = 0.4x0 - 0.4x10.5

    I = - 4.2 kg. m/s

    The minus signal indicates the direction, so the magnitude is 4.2 kg. m/s
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