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27 November, 22:41

A patient is given 40.00 mg of iodine-131 (131I) 131 53

The half-life of 53 I is 8 days.

How many milligrams of the 131I remains in the

patient after 32 days?

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Answers (1)
  1. 28 November, 01:53
    0
    2.5 mg

    Explanation:

    We are given;

    Original mass of I-131 is 40.0 mg Half life of I-131 is 8 days Number of days 32 days

    We are required to determine the mass that will remain;

    Using the formula;

    N = N₀ * 0.5^n

    where, N is the remaining mass, N₀ is the original mass, and n is the number of half lives.

    Therefore;

    n = time : half life

    = 32 days : 8 days

    = 4

    Therefore;

    Remaining mass = 40.0 mg * 0.5^4

    = 2.5 mg

    Hence, the remaining mass of I-131 after 32 days is 2.5 mg
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