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5 March, 22:38

a bus is moving with a constant velocity 10m/s along horizontal rode. a man standing inside bus throws ball virtically upward with valocity 8 m/sec WRT tohimself and cathes the ball. the magnitude of displacment of ball WTR ground will be

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  1. 6 March, 01:53
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    16.3 m

    Explanation:

    v₀ = 8 m/s

    v = - 8 m/s

    a = - 9.8 m/s²

    Find: t

    v = at + v₀

    (-8 m/s) = (-9.8 m/s²) t + (8 m/s)

    t = 1.63 s

    The displacement of the ball with respect to the ground is:

    x = vt

    x = (10 m/s) (1.63 s)

    x = 16.3 m

    Round as needed.
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