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12 December, 01:21

An object is shot upwards, from the ground, with an initial velocity of 120

m/s. How high will it be after 4. Os?

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Answers (1)
  1. 12 December, 02:44
    0
    Answer: 30 metres

    Explanation:

    Initial velocity of object = 120m/s

    Time taken = 4.0s

    Distance covered by object = ?

    Recall that distance = (Change in velocity / Time taken)

    Distance = (120m/s) / 4.0s

    = (120m/s) / 4.0s

    = 30m

    Thus, the object will be 30 metres high
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