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14 January, 16:57

The escape velocity of a bullet from the surface of planet Y is 1919.0 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.37 times that of Y, and its radius is 0.935 times the radius of Y

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  1. 14 January, 19:01
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    1584.9 m/s

    Explanation:

    Escape velocity on planet X is given as:

    v = √ (2*G*M/R)

    Where G = gravitational constant

    M = mass of planet X

    R = radius of planet X

    => 1919 = √ (2 * 6.67 * 10^ (-11) * M/R)

    1919² = (2 * 6.67 * 10^ (-11)) * M/R

    => M/R = 3682561 / (2 * 6.67 * 10^ (-11))

    M/R = 2.76 * 10^16 kg/m

    Given that

    Mass of planet X, M = 1.37 * mass of planet Y, m

    m = M/1.37 = 0.73M

    Radius of planet X, R = 0.935 * radius of planet Y, r

    => r = R/0.935 = 1.07R

    Hence, the escape velocity on planet Y is:

    v = √ (2 * 6.67 * 10^ (-11) * m/r)

    Inputting the values of m and r in terms of M and R:

    v = √ (2 * 6.67 * 10^ (-11) * 0.73M/1.07R)

    Given that M/R = 2.76 * 10^16:

    v = √ (2 * 6.67 * 10^ (-11) * 0.73 * 2.76 * 10^16 / 1.07)

    v = √ (25.12 * 10^5)

    v = 1584.9 m/s
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