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11 May, 09:22

A light plane is headed due south with a speed of 200 km/h relative to still air. After 1.00 hour, the pilot notices that they have covered only 137 km and their direction is not south but 15.0∘ east of south. What is the wind velocity?

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  1. 11 May, 09:58
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    Answer: the total velocity of the air is 67.69km/h to the north and 35.4km/h to the east.

    Explanation: The initial velocity of the plane is 200km/h south (supose that south is our positive x-axis here and east is the positive y-axis)

    In one hour, the plane is located 137km away from the initial position, and the position in X is equal to 137km*cos (15°) = 132.33, this means that the velocity in the x axis is equal to 132.33 km/h, knowing that the initial velocity of the plane was 200km in the x-axis, this means that the velocity of the air must be:

    132.33km/h - 200km/h = - 67.69km/h

    km and the position in "y" is equal to 137km*sin (15°) = 35.4km

    This means that the velocity of the air in the y-axis is 35.4km/h

    So the total velocity of the air is 67.69km/h to the north and 35.4km/h to the east.
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