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14 January, 19:43

Carbon-14 has a half-life of 5,700 years. How long will it take for 6.25% of the Carbon-14 to be remaining?

Answers (1)
  1. J
    14 January, 23:27
    0
    22,800 years

    Explanation:

    Half life equation:

    A = A₀ (½) ^ (t / T)

    where A is the final amount,

    A₀ is the initial amount,

    t is time,

    and T is the half life.

    0.0625 = (½) ^ (t / 5700)

    log 0.0625 = (t / 5700) log 0.5

    4 = t / 5700

    t = 22,800

    It takes 22,800 years.
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