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19 August, 21:57

Oscilloscope time base problem. You are asked to display a 1 kHzsine wave signal on the screen. Since the period T is related tothe frequency f by the formula T = 1 / f, the period of this waveis 1 / (103/s) = 1ms, so a reasonable setting for the"Time/div" dial is 1 ms/div. But suppose you select aninappropriate setting for the Time/div dial by mistake. What wouldyou see if you set the dial on 1 μ s/div?100 ms/div? A. Asine wave shifted to the left on 1 μ s/div and to the right on100 ms/divB. A (nearly) horizontal line on 1 μ s/div andmany (nearly) vertical lines of 100 ms/divC. Nothing on either (no trigger) D. Anormal sine wave in both casesE. None of these

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  1. 20 August, 00:14
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    B.

    Explanation:

    If we need to show on the screen a sine wave of 1 Khz, this means that the period (time to complete one cycle), will be 1/f = 1 ms.

    So, in order to show some cycles on the screen at the same time, it is reasonable to choose a 1ms/div setting for "Time/div" dial.

    If we by mistake choose a much much shorter setting (like 1 μs/div), what we will look at the screen will be very different, as we will be looking at 1/1000 of a cycle per div, so we wil see a nearly horizontal line.

    If instead we choose 100 ms/div, this means that each division will show 100 cycles of the sine wave, that they will look at if they were a lot of nearly vertical lines very closely spaced.

    So, the statement B). is the one that is true.
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