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20 March, 09:57

A block slides down a frictionless incline with constant acceleration. After sliding 6.80 m down, it has a speed of 3.80 m/s. What was the speed when the block had slid 3.40 m down? O 1.90 m/s O 2.69 m/s O None of the above

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  1. 20 March, 13:23
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    speed when the block had slid 3.40 m is 2.68 m/s

    Explanation:

    given data

    distance = 6.80 m

    speed = 3.80 m/s

    to find out

    speed when the block had slid 3.40 m

    solution

    we will apply here equation of motion that is

    v²-u² = 2*a*s ... 1

    here s is distance, a is acceleration and v is speed and u is initial speed that is 0

    so put here all value in equation 1 to get a

    v²-u² = 2*a*s

    3.80²-0 = 2*a*6.80

    a = 1.06 m/s²

    so

    speed when distance 3.40 m

    from equation 1 put value

    v²-u² = 2*a*s

    v²-0 = 2*1.06*3.40

    v² = 7.208

    v = 2.68

    so speed when the block had slid 3.40 m is 2.68 m/s
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