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9 June, 22:56

A quantity of 30.1 cm^3 of water at 22.4°C is placed in a freezer compartment and allowed to freeze to solid ice at - 7.2°C. How many joules of energy must be withdrawn from the water by the refrigerator?

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  1. 10 June, 00:54
    0
    13330.86 J

    Explanation:

    mass of volume of 30.1 cc of water = density x volume

    = 1 x 30.1 = 30.1 gm

    = 30.1 x 10⁻³ kg

    Heat to be withdrawn to cool water from 22.4 degree to 0 degree

    = mass x specific heat x fall of temperature

    = 30.1 x 10⁻³ x 4186 x 22.4

    = 2822.36 J

    Heat to be withdrawn to cool water 0 degree ice

    mass x latent heat of freezing

    30.1 x 10⁻³ x 334000

    = 10053.4 J

    Heat to be withdrawn to cool ice from 0 degree to - 7.2 degree

    mass x specific heat of ice x fall of temperature

    = 30.1 x 10⁻³ x 2100 x 7.2

    = 455.1 J

    Total heat to be withdrawn

    = 2822.36 + 10053.4 + 455.1

    = 13330.86 J
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