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16 March, 21:54

What is the minimum amount of energy required for an 80-

kgclimber carrying a 20 - kg pack to climb Mt. Everest, 8850

mhigh?

+3
Answers (1)
  1. 17 March, 01:16
    0
    minimum amount of energy required is 8.673 MJ

    Explanation:

    given data

    mass m1 = 80 kg

    additional mass m2 = 20 kg

    height = 8850 m

    to find out

    minimum amount of energy required

    solution

    we know here total mass is m = m1 + m2

    m = 80 + 20

    m = 100 kg

    so now apply energy equation for climb high that is

    energy = m*g*h ... 1

    here m is mass and g is 9.8 and h is height

    put here all value in equation 1

    energy = m*g*h

    energy = 100 * 9.8*8850

    energy = 8673000 J

    so minimum amount of energy required is 8.673 MJ
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