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22 February, 08:36

Two charges q1 and q2, that are distance d apart, repel each other with a force of 6.40 N. what would be the force between two charges q1 and = 2q and q2=3q, that are distance d apart?

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  1. 22 February, 11:18
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    Q: Two charges q1 and q2, that are distance d apart, repel each other with a force of 6.40 N. what would be the force between two charges q1'=2q1 and q2'=3q2 that that are distance d apart?

    Answer:

    The force = 38.4 N

    Explanation:

    From coulombs law,

    F = kq₁q₂/r² ... Equation 1

    Where F = Force of attraction or repulsion between the charges, q₁ and q₂ = first and second charge respectively, r = distance between the charges, k = constant of proportionality.

    When, F = 6.4 N, r = d m.

    6.4 = kq₁q₂/d² ... Equation 1

    When q₁' = 2q₁, q₂' = 3q₂, r = d cm

    F = k (2q₁) (3q₂) / d²

    F = 6kq₁q₂/d² ... Equation 2

    Dividing Equation 1 by equation 2

    6.4/F = kq₁q₂/d² / (6kq₁q₂/d²)

    6.4/F = 1/6

    F = 6.4*6

    F = 38.4 N.

    Thus the force = 38.4 N
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