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15 September, 09:55

A car slows from 22m/s to 3.0m/a at a constant rate of 2.1m/s. How many seconds are required before the car is traveling at 3.0m/s?

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  1. 15 September, 10:04
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    t = 9.05 s

    Explanation:

    Given,

    The initial velocity of the car, u = 22 m/s

    The final velocity of the car, v = 3.0 m/s

    The rate of change of speed of the car is 2.1 m/s,

    ∴ the acceleration, a = - 2.1 m/s²

    The acceleration and velocity is given by the relation

    a = (v - u) / t m/s²

    Therefore,

    t = (v-u) / a s

    Substituting the values in the above equation

    t = (3.0 - 22) / (-2.1)

    = 9.05 s

    Hence, the time required before the car is traveling at 3.0m/s is t = 9.05 s
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