An object initially traveling at a velocity of 52 m/s experiences an acceleration of 9.8 m/s^2 how much time will it take to come to rest

5.3 seconds

Explanation:

Vx = Vx0 + Ax. T

A = de-acceleration

Vx = 0 final at rest velocity

Vx0 = initial velocity

T = time to bring the object to a stop

therefore

0 = 52 m/s - (9.8 m/s^2). T

-52 m/s / - 9.8 m/sec^2 = T

5.3 seconds = T