A baseball (m = 145 g) traveling 32 m/s moves a fielder's glove backward 25 cm when the ball is caught. What was the average force exerted by the ball on the glove?

297 N

Explanation:

First, find the acceleration of the ball.

Given:

Δx = 0.25 m

v₀ = 32 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s) ² = (32 m/s) ² + 2a (0.25 m)

a = - 2048 m/s²

Find the force exerted on the ball by the glove.

F = ma

F = (0.145 kg) (-2048 m/s²)

F = - 297 N

The force exerted by the ball on the glove is equal and opposite.

-F = 297 N

Round as needed.