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6 August, 22:19

A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a

pressure of 468 kPa and its temperature is 8*C. What was the temperature the previous day?

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Answers (1)
  1. 6 August, 23:43
    0
    20 °C

    Explanation:

    Ideal gas law:

    PV = nRT

    Rearranging:

    P / T = nR / V

    Since n, R, and V are constant:

    P₁ / T₁ = P₂ / T₂

    488.2 kPa / T = 468 kPa / 281.15 K

    T = 293.29 K

    T = 20.1 °C

    Rounded, the temperature was 20 °C.
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