Ask Question
10 March, 11:42

If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R = V^ 2 R)

+5
Answers (1)
  1. 10 March, 11:50
    0
    1/4

    Explanation:

    P = IV, and V = IR, so P = I²R.

    If R is held constant, and I is cut in half, then power becomes:

    P = (I/2) ²R

    P = 1/4 I²R

    So the power reduces by a factor of 4.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R = V^ 2 R) ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers