What fraction of the horse's weight is borne by the front hooves?

Answer: 3056N

Explanation:

Torque = rF

Since left side of the torque=right side of the torque

1.1 (5000-x) = (1.8-1.1) (x)

x (weight of the front side), x=3055.56

Fraction of the horses weight = (weight of the front side) / (total weight)

1.8m/1.1m = 1.636m

Then, 5000N/1.636m = 3056N