Ask Question
25 October, 03:22

A (n) 12 g object moving to the right at 29 cm/s overtakes and collides elastically with a 24 g object moving in the same direction at 14 cm/s. Find the velocity of the slower object after the collision. Answer in units of cm/s.

+2
Answers (1)
  1. 25 October, 05:28
    0
    Answer: 16.9cm/s

    Explanation:

    According to the principle of conservation of linear momentum which states that the sum of momentum of bodies before collision is equal to the sum of their momentum after collision.

    Momentum = mass * velocity of the body

    Let m1 be mass of the first body = 12g

    m2 be mass of the second body = 29cm/s

    v1 be velocity of the first body = 24g

    v2 be velocity of the second body = 14cm/s.

    Note that both objects will move with a common velocity (v) after collision. Using the formula

    m1v1 + m2v2 = m1v + m2v

    12 (24) + 29 (14) = (12+29) v

    288+406 = 41v

    694 = 41v

    v = 694/41

    v = 16.9cm/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A (n) 12 g object moving to the right at 29 cm/s overtakes and collides elastically with a 24 g object moving in the same direction at 14 ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers