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27 October, 06:11

A parallel-plate capacitor is charged by a 14.0 V battery, then the battery is removed. You may want to review (Pages 692 - 695). Part A What is the potential difference between the plates after the battery is disconnected

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  1. 27 October, 08:19
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    Potential Difference = 14 V

    Explanation:

    We are told that when the capacitor plates are charged to a certain voltage, then we have;

    ΔV = 14 volts

    Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;

    ΔV = Q/C

    Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.

    Thus;

    Potential Difference = 14 V
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