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10 November, 12:49

A (n) 19000 kg freight car is rolling along a track at 1.5 m/s. Calculate the time needed for a force of 2600 N to stop the car.

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  1. 10 November, 13:13
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    Answer: 10.96secs

    Explanation:

    According to newton's second law

    Force = mass * acceleration

    F = ma

    F = m (v-u) / t

    Cross multiplying we have

    Ft = m (v-u)

    t = m (v-u) / F

    Given F = 2600N m = 19,000kg v = 1.5m/s u = 0m/s

    Substituting this values in the formula for the time we have

    t = 19000 (1.5-0) / 2600

    t = 28,500/2600

    t = 10.96secs
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