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30 October, 09:31

a force 10N drags a mass 10 kg on a horizontal table with acceleration 0.2m/s. If the acceleration due to gravity is 10m/s2, a coefficient of friction between the moving mass and a table is?

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  1. 30 October, 11:38
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    Explanation: 0.02

    Recall: μ mg = ma

    μ = ?

    m = 10N

    g = 10m/s2

    a = 0.2m/s

    Substituting the values, we have

    μ x 10 x 10 = 10 x 0.2

    100 μ = 2

    μ = 2/100

    μ = 1/50

    μ = 0.02

    μ = 0.02
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