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30 November, 15:57

Determine the average acceleration for x (t) = 19t^2+7t^3 for a time interval between 3 and 9 seconds

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  1. 30 November, 18:28
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    290

    Explanation:

    Average acceleration is the change in velocity over change in time.

    First, find the velocity by taking the derivative of position.

    v (t) = dx/dt

    v (t) = 38t + 21t²

    At t = 3 and t = 9:

    v (3) = 303

    v (9) = 2043

    So the average acceleration is:

    a = Δv / Δt

    a = (2043 - 303) / (9 - 3)

    a = 290

    Use appropriate units.
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