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12 June, 05:27

An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-14 N, what is it's speed?

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  1. 12 June, 06:46
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    The speed of the electron is v = 1.01 x 10¹⁵ m/s

    Explanation:

    Given data,

    The mass of the electron, m = 9.11 x 10⁻³¹ kg

    The radius of the circle, r = 2.00 x 10⁻² m

    The force acting on electron, F = 4.60 x 10⁻¹⁴ N

    The speed of the electron, v = ?

    The centripetal force of the electron is given by

    F = mv² / r

    ∴ v² = Fr/m

    v = √ (Fr/m)

    Substituting the given values in the above equation,

    v = √ (4.60 x 10⁻¹⁴ x 2.00 x 10⁻² / 9.11 x 10⁻³¹)

    v = 1.01 x 10¹⁵ m/s

    Hence, the speed of the electron is v = 1.01 x 10¹⁵ m/s
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