A 4.0 kg bucket of water is raised from a well

by a rope.

The acceleration of gravity is 9.81 m/s?.

If the upward acceleration of the bucket is

2.8 m/s², find the force exerted by the rope

on the bucket of water.

1. 69.658

2. 52.84

3. 85.318

4. 70.86

5. 84.429

Draw a free body diagram of the bucket. There are two forces:

Tension force T pulling up.

Weight force mg pulling down.

Sum of forces in the y direction:

∑F = ma

T - mg = ma

T = mg + ma

T = m (g + a)

Given m = 4.0 kg, g = 9.81 m/s², and a = 2.8 m/s²:

T = (4.0 kg) (9.81 m/s² + 2.8 m/s²)

T = 50.44 N