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20 May, 01:43

Consider a horizontal, uniform board of weight 125 N and length 4 m that is supported by vertical chains at each end. A person weighing 500 N is sitting on the board. The tension in the right chain is 250 N

What is the tension in the left chain?

a. 250 N

b. 375 N

c. 500 N

d. 625 N

e. 875 N

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Answers (1)
  1. 20 May, 03:43
    0
    b. 375 N

    Explanation:

    System of forces in balance

    ΣFy = 0 Equation (1)

    Forces acting on the board

    T₁: Tension in the left chain, vertical and upward

    T₂ = 250 N : Tension in the right chain, vertical and upward

    W₁ = 125 N : Weight of the board, vertical and downward

    W₂ = 500 N : Weight of the person, vertical and downward

    Calculation of the T₁

    We apply the Equation (1)

    ΣFy = 0

    T₁+T₂-W₁-W₂ = 0

    T₁ = - T₂+W₁+W₂

    T₁ = - 250 N + 125 N + 500 N

    T₁ = 375 N
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