an 100kg object traveling at 50m/s collides (perfectly inelastic) with a 50kg object initially at rest. what is the sum of the momentum of both objects prior to the collision?

Question

Physics

Gideon Mccullough

29 September, 01:30

an 100kg object traveling at 50m/s collides (perfectly inelastic) with a 50kg object initially at rest. what is the sum of the momentum of both objects prior to the collision?

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Answers (1)

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Brennen Curtis · Answer 1

5000 kg. m/s

Explanation:

Before collision, momentum of 100 Kg is given by

p=mv where p is momentum, m is the mass of object and v is the velocity,

therefore, the momentum=100*50=5000 kg. m/s

The momentum of the 50 Kg is zero since it's at rest hence v=o

Total momentum before collision is therefore 5000+0=5000 kg. m/s