Ask Question
22 April, 03:46

Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron enters the region between them at a speed of 2.9 x 10^5 m/s by passing through a small hole in the negative plate and continues moving toward the positive plate. Assume the electric field between the plates is uniform.

(a) what is the electron's speed, in meters per second, when it is 0.1 cm from the negative plate?

+5
Answers (1)
  1. 22 April, 05:07
    0
    Electric field between plates

    V / d

    = 170 / (2 x 10⁻²)

    = 8500 N/C

    Force on electron in this field

    = 8500 x 1.6 x 10⁻¹⁹

    = 13600 x 10⁻¹⁹ N

    Acceleration

    = 13600 x 10⁻¹⁹ / 9.1 x 10⁻³¹

    a = 1494.5 x 10¹² m / s²

    s =.1 x 10⁻² m

    v² = u² + 2as

    = (2.9x 10⁵) ² + 2 x 1494.5 x 10¹² x. 1 x 10⁻²

    = 8.41 x 10¹⁰ + 299 x 10¹⁰

    = (8.41 + 299) x 10¹⁰

    v = 17.53 x 10⁵ m / s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron enters the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers