Ask Question
8 January, 17:27

Suppose that two objects attract each other with a gravitational force of 16 units. if the mass of object one was doubled, and if the distance between the objects was tripled, then what would be the new force of attraction?

+5
Answers (1)
  1. 8 January, 21:13
    0
    Answer: 3.5units

    Explanation:

    Gravitational force existing between the two masses is directly proportional to the product of their masses and inversely proportional to the square of the distances between the masses.

    Mathematically, F = GMm/r^2

    G is the gravitational constant

    M and m are the masses

    r is the distance between the masses.

    If the force of attraction between the masses is 16units, it becomes,

    16 = GMm/r^2 ... (1)

    If the mass of object 1 is doubled and distance tripled, we will have

    F = G (2M) m / (3r) ^2

    F=2GMm/9r^2 ... (2)

    Solving eqn 1 and 2 to get the new Force

    Dividing eqn 1 by 2, we have

    16/F = GMm/r^2 : 2GMm/9r^2

    16/F = GMm*9r^2/r^2*2GMm

    16/F = 9/2 (upon cancelation)

    Cross multiplying we have

    9F=32

    F = 32/9

    F = 3.5units
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose that two objects attract each other with a gravitational force of 16 units. if the mass of object one was doubled, and if the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers