n this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m/s2. Ignore air resistance. Part APart complete A flea jumps straight up to a maximum height of 0.520 m. What is its initial velocity v0 as it leaves the ground

U=3.19m/s

Explanation:

using the newton's equation of motion as

s=ut+1/2at^2

S=distance

H=height the jumping flea attains

g=acceleration due to gravity

a=acceleration of the body

Therefore, a body under free fall

a=-g

s=h

h=0.520m

g=9.80m/s^2

V^2 = u^2-2*9.80*.52

V=o at maximum height

0=u^2-10.192

u=3.19m/s

Definition of terms

Velocity:

change in displacement per time

Acceleration: Is change in velocity per time