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11 July, 01:07

The difference in potential between the accelerating plates of a T. V. set is about 30 kV. If the distance between these plates is 1.3 cm, find the magnitude of the uniform electric field in this region.

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  1. 11 July, 02:42
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    2.31 * 10^6 V/m

    Explanation:

    The relationship between potential difference and electric field is given as:

    V = E * r

    => E = V/r

    V = 30kV = 30000V

    r = 1.3cm = 0.013m

    E = 30000/0.013

    E = 2.31 * 10^6 V/m
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