The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including

crew) has a mass of 230. kg and an initial velocity of 4.00 m/s, what is the displacement

of the boat in 5.00 seconds? (Be sure to draw a FBD).

Question

Physics

Sabrina Shaffer

13 May, 04:40

The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including

crew) has a mass of 230. kg and an initial velocity of 4.00 m/s, what is the displacement

of the boat in 5.00 seconds? (Be sure to draw a FBD).

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Answers (1)

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Emilio · Answer 1

180^2 + 390^2 = force ^2 (Pythagoras) root of force^2 = 429.5N approx resultant force Acceleration = Force/Mass 429.5/270 = 1.5907 ms^-2 in a Southwesterly direction.

The forces acting on a sailboat are 390. N south and 180. N east. If the boat (includingcrew) has a mass of 230. kg and an initial velocity of 4.00 m/s, what is the displacementof the boat in 5.00 seconds? (Be sure to draw a FBD).

The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including

crew) has a mass of 230. kg and an initial velocity of 4.00 m/s, what is the displacement

of the boat in 5.00 seconds? (Be sure to draw a FBD).