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23 October, 14:18

A refrigerator is used to cool water from 23°C to 5°C in a continuous manner. The heat rejected in the condenser is 570 kJ/min and the power is 2.65 kW. Determine the rate at which water is cooled in L/min and the COP of the refrigerator. The specific heat of water is 4.18 kJ/kg·°C and its density is 1 kg/L.

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  1. 23 October, 16:20
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    Answer: Q=5.46 L/s

    COP=2.58

    Explanation:

    Given that

    Cp = 4.18 kJ / (kg. C

    density = 1 kg/L

    Heat rejected Qr = 570 kJ/min

    Power in put W = 2.65 KW

    From first law of thermodynamics

    U = W + q

    q = Heat absorbed

    U = internal energy

    W = workdone

    U = 570 kJ/min = 9.5 KW

    9.5 = 2.65 + q

    q = 6.85 KW

    COP = q/W

    COP = 6.58 / 2.65

    COP=2.58

    Lets take volume flow rate is Q

    So mass flow rate of water m = ρ Q

    q = m Cp ΔT

    6.85 = 1 x Q x 4.18 (23-5)

    Q=0.091 L/min

    Q=5.46 L/s
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