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17 May, 17:12

What height (displacement) will a ball reach if thrown upward with an initial velocity of 15 m/s

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Answers (1)
  1. 17 May, 17:59
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    11.48 m

    Explanation:

    initial velocity (u) = 15 m/s

    acceleration due to gravity (g) = 9.8 m/s

    final velocity (v) = 0 (the ball's speed reduces gradually when thrown until

    becomes 0 at maximum height)

    find the height reached.

    height (s) = ut + 0.5 at^{2}

    we cannot apply this formula directly because we do no know the time

    (t), so we first need to find the time

    v = u + at

    0 = 15 + (-9.8 x t) (the negative sign is because the ball is decelerating

    upwards)

    15 = 9.8t

    t = 1.53 s

    now that we have the time we can put it into the initial equation height (s) = ut + 0.5 at^{2}

    height (s) = (15 x 1.53) + (0.5 x (-9.8) x 1.53^{2})

    height = 22.95 - 11.47 = 11.48 m
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