An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m

Question

Physics

Emelia

17 February, 19:20

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m

+1

Answers (2)

Know the Answer?

Bridger Bryant · Answer 1

C) 1.0 m

Explanation:

The component of the velocity parallel to the sidewalk is:

vₓ = v cos θ

vₓ = 0.1 m/s cos 45°

vₓ = 0.0707 m/s

The distance traveled after 14 seconds is:

d = vₓ t

d = (0.0707 m/s) (14 s)

d = 0.99 m

Closest answer is C) 1.0 m.

Jacqueline Burke · Answer 2

C) 1.0m

Explanation:

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, it will have traveled 1.0m in the direction parallel to the edge of the sidewalk.

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?A) 0.005mB) 0.01mC) 1.0mD) 9.9m

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m