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14 October, 08:02

The electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 300 m the field has magnitude 60.0 N/C; at an altitude of 200 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 100 m on edge, with horizontal faces at altitudes of 200 and 300 m.

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  1. 14 October, 10:42
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    q = 3.356*10^-6C

    Explanation:

    In a cube of air, the electric field is perpendicular to the top and bottom of the cube, the total reflux = reflux200 + reflux300

    But reflux is given by:

    Reflux = E*A = E*A cos theta.

    Where theta is the angle between the area vector and the electric field.

    Total reflux = E300*A cos180 + E200*A cos0

    Total reflux = - E300A + E200A

    Total reflux = A (E300-E200)

    Total reflux is given by Guass's law = Total reflux = q/Eo

    q=Eo*total reflux

    q = EoA (E200-E300) q = (8.84*10^-12) (100) ^2 * (100-60)

    q=3.356*10^-6C
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