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11 December, 18:43

15 J of work were expended moving an 18 kg block. At what velocity did the block move?

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  1. 11 December, 19:31
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    Answer:√ (5/3) m/s

    Explanation:

    Kinetic energy (ke) = 15j

    Mass (m) = 18kg

    Velocity (v) = ?

    Ke = (mxv^2) / 2

    15 = (18xv^2) / 2

    Cross product

    (18xv^2) = 15x2

    18xv^2=30

    Divide both sides by 18

    (18xv^2) ➗ 18=30 ➗ 18

    v^2=5/3

    v=√ (5/3)

    v=√ (5/3) m/s
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