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13 April, 22:43

What current flow (I) is associated with an input voltage of 8.0V and resistors R1 = 2.5 kiloohms and R2 = 3.5 kiloohms? Calculate this value in mA

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  1. 14 April, 01:18
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    current in series is 1.33 mA

    current in parallel is 5.48 mA

    Explanation:

    given data

    voltage = 8 V

    resistors R1 = 2.5 kilo ohms

    resistors R2 = 3.5 kilo ohms

    to given data

    current flow

    solution

    current flow in series is express as

    current = voltage / resistor

    put here all value

    current = 8 / (2.5 + 3.5)

    current = 8 / 6

    current = 1.33 mA

    and

    current flow in parallel is express as

    current = voltage / resistor

    put here all value

    current = 8 / (1 / (1/2.5 + 1/3.5))

    current = 8 / 1.45

    current = 5.48 mA
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