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5 March, 12:06

A charge of 5.67 x 10-18 C is placed 3.5 x 10 m away from another charge of - 3.79 x 10 "C

What is the force of attraction between them?

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  1. 5 March, 13:44
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    1. 579 x 10 ^-22N

    Explanation:

    F = kq1q2/r^2

    = 9.0 x 10^9 x 5.67 x 10^-18 x 3.79 x 10^-18 / (3.5 x 10^-2) ^2

    = 1. 579 x 10 ^-22N
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