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31 March, 09:42

A 35-N bucket of water is lifted vertically 3.0 m and then returned to its original position. How much work did gravity do on the bucket during this process?

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Answers (2)
  1. 31 March, 11:14
    0
    W = 105 J

    Explanation:

    Given: F = 35 N, D = 3.0 m

    W=?

    Sol:

    Work done = Force * distance

    W = 35 N * 3 = 105 J
  2. 31 March, 11:43
    0
    0 J

    Explanation:

    From the question, let us assume that a positive work was done in lifting the bucket down and a negative work was done in lifting the bucket up.

    Going up

    W = - Fd ... Equation 1

    Where W = work done, F = Force needed to lift the bucket, d = distance

    Given: F = 35 N, d = 3.0 m

    Substitute into equation 1

    F = - 35 (3.0)

    F = - 105 N.

    Coming Down

    W = Fd

    Given: F = 35 N, d = 3.0 m

    W = 35 (3.0)

    W = 105 N.

    During the process (going up and coming down)

    ΔW = - 150+105

    ΔW = 0 J

    Hence the work done by gravity during the process = 0 J
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