at t=0s a car has a speed of 30m/s. at t=6s, its speed is 14m/s. what is its average acceleration during this time interval?

-2.666667 m/s²

Explanation:

v₂ - v₁ = at

t = 6 sec

v₂ = 14 m/s

v₁ = 30 m/s

a = - 2.666667 m/s²

Answer:-8/3 m/s^2

Explanation:

acceleration = (change in velocity) / time

Acceleration = (v-u) / t

Acceleration = (14-30) / 6

Acceleration=-16/6

Acceleration=-8/3 m/s^2

The car is decelerating