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6 December, 22:11

A 2.00-kg copper rod is 50.00 cm long at 23°C. If 40 000 J are transferred to the rod by heat, what is its change in length? ccopper = 387 J/kg·°C and αcopper = 17 * 10-6/°C.

a. 0.022 cm

b. 0.044 cm

c. 0.059 cm

d. More information is needed

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  1. 7 December, 00:42
    0
    0.044 cm

    Explanation:

    mass of copper, m = 2 kg

    length of rod, l = 50 cm

    T1 = 23°C

    Heat, Q = 40000 J

    specific heat of copper, c = 387 J/kg°C

    α = 17 x 10^-6 / °C

    Let the change in the length of copper is Δl.

    heat = mass x specific heat x ΔT

    40000 = 2 x 387 x ΔT

    ΔT = 51.68

    Now use the formula for the linear expansion

    Δl = l x α x ΔT

    Δl = 50 x 17 x 10^-6 x 51.68

    Δl = 0.044 cm

    Thus the increase in length of rod is 0.044 cm.
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