The electric field at the surface of a charged, solid, copper sphere with radius 0.230 m is 4100 N/C, directed toward the center of the sphere. What is the potential at the center of the sphere, if we take the potential to be zero infinitely far from the sphere?

Given Information:

Electric field = E = 4100 N/C

Radius of sphere = r = 0.230 m

Required Information:

Potential = V = ?

Answer:

Potential = 9.43*10² Volts

Explanation:

The relation between electric field and potential is given by

V = Er

Where E is the electric field at the surface of charged sphere and r is the radius of sphere

V = 4100*0.230

V = 9.43*10² N. m/C

1 Volt is equal to 1 N. m/C

V = 9.43*10² Volts

Therefore, the potential at the center of the sphere is 9.43*10² Volts.

943 Nm/C

Explanation:

Parameters given:

Radius of sphere, r = 0.23 m

Field at the surface of sphere, E = 4100 N/C

Electric potential is given as:

V = E * r

The electric potential at the center of the sphere will be the product of electric field at the center and the distance between the surface and center (radius).

V = 4100 * 0.23

V = 943 Nm/C